Particle 1, mass 1 kg, is moving to the right at 1 m/s. Particle 2, mass 3/2 kg, is moving to the left at 3/2 m/s. The particles collide. After the collision, particle 1 is moving to the left at 1 m/s. What is the velocity of particle 2? Was the collision elastic or inelastic?
With x increasing to the right, the total momentum of the system
|Px||(1 kg)(1 m/s) - (3/2 kg)(3/2 m/s)||(1 kg)(-1m/s)+(3/2 kg)vx|
Setting the value before equal to the value after, we get:
-5/4 kg· m/s = -1 kg· m/s + (3/2 kg)vx
vx = -(1/4)(2/3) m/s = -1/6 m/s
Since the particles have different velocities, we can immediately conclude that the collision is NOT totally inelastic. Now let's calculate the kinetic energy:
Kbefore = 1/2(1 kg)(1 m/s)2 + 1/2(3/2 kg)(3/2 m/s)2 = (1/2 + 9/16) J = 17/16 J
Kafter = 1/2(1 kg)(1 m/s)2 + 1/2(3/2 kg)(1/6 m/s)2 = (1/2 + 1/48) J = 25/48 J
The total kinetic energy is less after the collision, so the collision is inelastic, but not totally inelastic.
We can see this easily if we look in the CM frame:
In the CM frame, the speed of each particle has decreased. Thus the total kinetic energy of the system has decreased.