1. Draw the field-line diagram. Do you have enough symmetry to use Gauss' law? Discuss!!

Since the system is spherically symmetrical, and can be rotated through
any angle without changing anything, then there is enough symmetry to use
Gauss' law. Notice that some field lines begin inside the sphere
of radius *a.*

2. Construct a Gaussian surface that you can use to apply Gauss' law
in order to find the electric field at a point P with *r>a. *Describe
how you chose your volume. Draw it on the diagram. Label its dimensions.

The surface is chosen to be perpendicular or parallel to the electric
field lines at each point. Thus it is also a sphere, inside the original
sphere, with radius *r < a.*

3. Find the flux through your surface. Be sure to explain **each step**
clearly and carefully.

From here the solution follows Example 24.1 exactly, and the example
we did in class. Because of the symmetry, **E **is radial and
the r-component has a constant value over the surface that we have chosen,
so the flux is 4(pi)r^{2}E_{r} .

4. Now find the charge inside the surface.

The charge density inside the whole sphere is Q/(4pi a^{3}/3)
and the charge inside our Gaussian surface is

5. Apply Gauss' law to find the electric field vector. Comment on your
result, and how it corresponds to your field line diagram.

Setting flux through surface = charge inside/epsilon we get

Thus the field strength increases from 0 to r = a, and at r = a we get kQ/a